Sum of first 3 rd terms in AP is 24 and the sum of their squares is 224. Find the first 3rd terms in AP
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4,8,12.. Arithmetic Progression!
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let the terms be a-d, a, a+d
sum=a-d+a+a+d=3a=24
a=8
Now terms become
8-d, 8,8+d
sum of squares=224
(8-d) ^2+64+(8+d)^2=224
from here u will get d...
put it in terms taken
sum=a-d+a+a+d=3a=24
a=8
Now terms become
8-d, 8,8+d
sum of squares=224
(8-d) ^2+64+(8+d)^2=224
from here u will get d...
put it in terms taken
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