sum of first 3 terms of an AP is 15 If the sum of their squares is 93 Find the AP
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a+a+d+a+2d=15
3a+3d=15
a+d=5------------(1)
a*a+a+d*a+d+a+2d*a+2d=93
3a+3d=15
a+d=5------------(1)
a*a+a+d*a+d+a+2d*a+2d=93
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