Question

Sum of first 30 integers which are a multiple of 6?




pls don't write unnecessary words as an answer, or else I have to report you!​

Answer 1

Answer:

2790

Step-by-step explanation:

The numbers that are divisible by 6 are 6,

=15[12+174]

=15(186)

= by 6 is 2700.Sn=2n(2a+(n−1)d) 

⇒Sn=230[2(6)+(30−1)6] 

⇒Sn=15(12+29×6) 

⇒Sn=15(12+174) 

⇒Sn=15×186

⇒Sn=2790