Question

Sum of first 30 terms of ap whose nth term is 3+2n

Answer 1

Answer:

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Answer 2

Sum of first 30 terms of AP is 1020.

Step-by-step explanation:

Given : A.P whose nth term is $a_n=3+2n$.

To find : Sum of first 30 terms of A.P ?

Solution :

nth term is $a_n=3+2n$

Put n=1,

$a_1=3+2(1)=5$

Put n=2,

$a_2=3+2(2)=7$

Common difference is $d=a_2-a_1$

$d=7-5$

$d=2$

The first term is a=5 and common difference is d=2.

The sum of n terms is given by,

$S_n=\frac{n}{2}[2a+(n-1)d]$

Here, n=30 substitute the values,

$S_{30}=\frac{30}{2}[2(5)+(30-1)2]$

$S_{30}=15[10+58]$

$S_{30}=15[68]$

$S_{30}=1020$

Sum of first 30 terms of AP is 1020.

#Learn more

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