Question

sum of first 32 odd natural number with solution

Answer 1

1,3,5,7...,are odd numbers are in Ap First term =a=1 Common difference = d = 3-1 =2 Number of terms =n =32 Sn= n/2[2a+(n-1)d] = 32/2[2*1+(32-1)2] =16*[2+62] =16*64 = 1024

Answer 2

odd number are 1357 are in AP

= 1, n=32,d=2 therefore SN is equal to 1 upon 2 into 2 A Plus and minus 1 into d

832 is equal to 32 upon 2 into 2 into 1 + 32 - 1 into two therefore necessary to is equal to 32.2 into 64 therefore s32 is equal to 1024