Question

Sum of first 33th terms of an AP is 1320 find its 17th term​

Answer 1

Step-by-step explanation:

S33 = n/2 [2a+(n-1) d]

1320 = n/2 [ 2a + nd -d]............ (1)

1320×2 = 33 [ 2a + nd -d]

2640 = 33 [ 2a + 33 - 1]

2640 = 33 [ 2a + 32]

2640 = 66 a + 1056

66a = 1584

a= 24

tn= a+(n-1)d

t17 = 24 + 16

t17 = 40

Answer 2

N/2 ( a + l )

33/2 ( a + 33) = 1320