Math, asked by suknfkk, 1 year ago

sum of first 40+ve integers which are divisible by 6

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Answered by kushalpandey8858

0

I think that it will help you

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Answered by nandinibhandari111

0

n=40

a.p=6,12,18.........

sn=n/2(2a+(n-1)d)

d=6

sn=40/2(2*6+39*6)

sn=20(12+234)

sn=20(246)

sn=4920

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