sum of first 40 whole numbers
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What will be the sum of whole number from 1 to 40?
Sum of first n whole numbers = (n)(n+1)/2
Sum of 40 whole numbers = (40)(40+1)/2
Sum of 40 whole numbers = (20)(41)
Sum of 40 whole numbers = 820
Sum of first n whole numbers = (n)(n+1)/2
Sum of 40 whole numbers = (40)(40+1)/2
Sum of 40 whole numbers = (20)(41)
Sum of 40 whole numbers = 820
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Answer:
Explanation:
820.....
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