Question

sum of first 50 odd numbers​

Answer 1

first term (a)= 1

common difference (d)= 2

nth term= a+(n-1)d

50th term= 1+(50-1)2

= 1+49×2 = 99

sum = [n(a1+a50)]÷2

= [50(1+99)]÷2

= 2500