Question

Sum of first 50 odd numbers between 100 to 250 ?

Answer 1

Hope it will be helpful to you

Answer 2

Answer:

n = 50

a =101

a2=103

so,d=a2-a1

103-101=d

d=2

so,(an=249)

=-: we know

Sn=n/2(2a +(n-1 )d)

Sn=n/2 (a + an)

Sn=50/2(101+249)

Sn=50/2(350)

Sn=50*175

Sn== 8750

So, req. sum is 8,750.