Sum of first 51 terms if 2nd term is 14 and 3rd is 18
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Answer:
Step-by-step explanation:
a +1 d =14
subtract a +2 d =18
-1 d = -4
d = 4
a + 4 = 14 ⇒ a = 10
s = n/2 { 2a + (n-1)d} ⇒ s = 51/2 { 20 + 200 } ⇒ s = 5610
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