Question

sum of first 55 terms is an A. P. is 3300, find its 28th term. ​

Answer 1

Answer:

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Step-by-step explanation:

Let a and d be the first term and common difference of the given AP respectively.

Given, S55=3300

⇒255[2a+(55−1)d]=3300

⇒55[a+27d]=3300

⇒a+27d=60

Hence, 28th term a28=a+27d=60

Answer 2

Answer:

60

Step-by-step explanation:

Let a and d be the first term and common difference of the given AP respectively.

Given, $S_{55}$    = 3300

⇒  $\frac{55}{2}$    [ 2a + (55 − 1)d] = 3300

⇒ 55 [ a + 27 d ] = 3300

⇒ a + 27d = 60

Hence,  $28^{th}$ term $a_{28}$ = a + 27d = 60

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