Question

Sum of first 7 terms of an arithmetic sequence is 98 .Fnd the fourth term.​

Answer 1

Answer:

Hope this solution is helpful for u

Answer 2

Answer:

14

Step-by-step explanation:

Sum of 7 terms = 98

(7/2)(2xa+ (7-1)xd) = 98   {sum of n terms= (n/2)(2xa+(n-1)xd}

(7/2)x(2a+6d) =98

7x(a+3d) = 98

(a+3d)= 14 --------- 1

Now,

4th term= a+3d ---------2    

{ nth term of AP = a+(n-1)xd }

So from 1 and 2

fourth term = 14.