Question

sum of first and the second term of an A.P. is 11 and sum of 6th and 7th term is 41 find A.P

Answer 1

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Let first term be A common difference be D
then , A1 + A2 = 11
A + A + D = 11
2A + D = 11. ................1️⃣

A6 + A7 = 41
A+5D + A+6D = 41
2A + 11D = 41..............2️⃣

Subtract 1️⃣ from 2️⃣
you will get
D = 3

put the value D in 1️⃣

2A + 3 = 11
2A = 8
A = 4

then the A.P. is
4 , 7 , 10

Answer 2

ap are 4,7,10 of the question