sum of first hundred natural numbers according to progressions
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Find the sum of first 100 natural numbers. Clearly, it is an Arithmetic Progression whose first term = 1, last term = 100 and number of terms = 100. Therefore, the sum of first 100 natural numbers is 5050.
MARKBUSTER:
but
we will get 50(1+99)1
so it is 5000
no bro
ur correct I've taken only a instead of 2a in the formula
ur correct
Answered by
2
HERE IS YOUR ANSWER :
n (n+1)/2 where n is 100.
=100 (101)/2
=50 × 101
=5050
This is Arithmetic Progression.
PLS MARK MY ANSWER THE BRAINLIEST ONE.
n (n+1)/2 where n is 100.
=100 (101)/2
=50 × 101
=5050
This is Arithmetic Progression.
PLS MARK MY ANSWER THE BRAINLIEST ONE.
nope
I want procedure along with sn
Hey mate, now it's OK???
nope
another mate is correct
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