Sum of first hundred numbers common to the A.P's 12,15,18....and 17,21,25..... is
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Answer:
61500
Step-by-step explanation:
The terms common to two AP's is also an AP with common difference D=LCM(d1,d2) and first term A= first term common to the two series
Since 21 is the 1st term common to these series
d1=3
d2=4
D=LCM(3,4)=12
Therefore the resultant AP has a=21 and d=12
Finding sum of 100 terms:
S=(100/2)[2(21)+(99)(12)]
S=100(21+594)
S=61500
Hope this answer helped you
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