sum of first m terms of an AP is 0.if the first term is a, then the sum of next n terms is
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Step-by-step explanation:
The sum of first m terms =m/2(2a+(m-1)d)
0=2am+dm2-dm
0=2am+(m2-m)d
-2am/m2-m=d
put it in the sum of next n terms =n/2(2a(n-1)d)
=(an2-a)-2am/m2-m
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