Question

sum of first n natural numbers 1+2+3+4....+30(30+)=30×31by3​

Answer 1

Step-by-step explanation:

$sum \: of \: n \: natural \: numbers \\ \frac{n(n + 1)}{2} \\ n = 30 \\ = > \frac{30(30 + 1)}{2} \\ \frac{30 \times 31}{2} \\ = > 465$