Sum of first n natural numbers is 5 and square + 4 n find its 8 term
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Answered by
27
Given that, the sum of the first n Natural numbers
Sn = 5n² + 4n
Now,
S8 = 5 (8)² + 4 (8)
= (5 × 64) + 32
= 320 + 32
= 352
and
S7 = 5 (7)² + 4 (7)
= 5 (49) + 28
= 245 + 28
= 273
Thus, the 8th term is
= S8 - S7
= 352 - 273
= 79
#
Answered by
8
Heya !!!
Sn = 5N² + 4N
Therefore,
S8 = 5 × (8)² + 4 × 8
=> 320 + 32
=> 352
And,
S7 = 5 × (7)² + 4 × 7
=> 5 × 49 + 28
=> 245 + 28
=> 273
***************************
8th term = S8 - S7
=> 352 - 273
=> 79
HOPE IT WILL HELP YOU...... :-)
Sn = 5N² + 4N
Therefore,
S8 = 5 × (8)² + 4 × 8
=> 320 + 32
=> 352
And,
S7 = 5 × (7)² + 4 × 7
=> 5 × 49 + 28
=> 245 + 28
=> 273
***************************
8th term = S8 - S7
=> 352 - 273
=> 79
HOPE IT WILL HELP YOU...... :-)
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