sum of first n odd natural numbers in 961. what is the value of n
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Answered by
4
SUM OF FIRST N ODD NATURAL NUMBERS IS N^2=N*N
N*N=961
WE KNOW THAT 31*31=961
N*N=31*31
N^2=31^2
N=31
Answered by
5
The sequence consists of odd numbers : 1,3,5,7,9
First term , a=1
Common difference, d= 3-1 = 2
Sum of 'n' terms = 961
The formula is sn = n/2 ( 2a+(n-1)d)
961 = n/2 (2(1)+(n-1)2)
961 = n(1+n-1)
Both 1 and -1 will get cancel,
961 = n^ 2
n= √961
n= √31×31
n= 31
Hope this helps you friend
Thanks ✌️ ✌️
First term , a=1
Common difference, d= 3-1 = 2
Sum of 'n' terms = 961
The formula is sn = n/2 ( 2a+(n-1)d)
961 = n/2 (2(1)+(n-1)2)
961 = n(1+n-1)
Both 1 and -1 will get cancel,
961 = n^ 2
n= √961
n= √31×31
n= 31
Hope this helps you friend
Thanks ✌️ ✌️
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