Math, asked by sharad126, 7 months ago

sum of first n odd square number will be

Answers

Answered by Bhumiraghav
1
If n consecutive natural numbers are 1, 2, 3, 4, …, n, then the sum of squared 'n' consecutive natural numbers is represented by: 12 + 22 + 32 + … + n2.
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Sum of Squares of First n Odd Numbers.
Sum of: Formula
Squares of first odd natural numbers Σ(2n-1)2 =[n(2n+1)(2n-1)]/3
Answered by Anonymous
1

Answer:

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Step-by-step explanation:

If n consecutive natural numbers are 1, 2, 3, 4, …, n, then the sum of squared 'n' consecutive natural numbers is represented by: 12 + 22 + 32 + … + n2.

...

Sum of Squares of First n Odd Numbers.

Sum of: Formula

Squares of first odd natural numbers Σ(2n-1)2 =[n(2n+1)(2n-1)

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