Sum of first n term of an arith metic sequence is 3n^2-6n.
Calculate first term and common difference. Write the algebraic form
Find15 th term
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Step-by-step explanation:
Sn=3n2-6n
=>S1 or 1st term of the AP= 3(1)^2-6*1=3-6=-3
similarly 2nd term will be 0
then a2-a1=0-(-3)=3
=>cd=3
:.15th term= a+14d
= -3+14*3
=39
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