Sum of first n terms of ap is an^2+bn.find its common difference
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Animeshtewary:
Bro i have done upto .. 4a+2b-a-b on my one but cant understand the rest part...
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Solution:
_____________________________________________________________
Given:
Sum of n terms of an AP is an² + bn ,.
_____________________________________________________________
To find:
The common difference between the terms of the given AP,.
_____________________________________________________________
As, we know that,
![S_n = a + a_2 + a_3,...a_n S_n = a + a_2 + a_3,...a_n](https://tex.z-dn.net/?f=S_n+%3D+a+%2B+a_2+%2B+a_3%2C...a_n)
=>![S_n = a + (a+d) + (a+2d),...(a+(n-1)d) S_n = a + (a+d) + (a+2d),...(a+(n-1)d)](https://tex.z-dn.net/?f=S_n+%3D+a+%2B+%28a%2Bd%29+%2B+%28a%2B2d%29%2C...%28a%2B%28n-1%29d%29)
If n = 1,
=>![S_1 = a_1 = a S_1 = a_1 = a](https://tex.z-dn.net/?f=S_1+%3D+a_1+%3D+a)
=> a(1)² + b(1)
=> a + b,..
∴
,..
_______________________
If n = 2,
=>![S_2 = a_1 + a_2 S_2 = a_1 + a_2](https://tex.z-dn.net/?f=S_2+%3D+a_1+%2B+a_2+)
=>![S_2 = a + (a + d) S_2 = a + (a + d)](https://tex.z-dn.net/?f=S_2+%3D+a+%2B+%28a+%2B+d%29)
=> a(2)² + b(2) = a+b + a + b + d
=> 4a + 2b = 2a + 2b + d
=> 2a + 2b + d = 4a + 2b
=> d = 2a,.
_________________
∴ Common difference of the AP is 2a,.
_____________________________________________________________
Hope it Helps!!
=> Mark as Brainliest,..
_____________________________________________________________
Given:
Sum of n terms of an AP is an² + bn ,.
_____________________________________________________________
To find:
The common difference between the terms of the given AP,.
_____________________________________________________________
As, we know that,
=>
If n = 1,
=>
=> a(1)² + b(1)
=> a + b,..
∴
_______________________
If n = 2,
=>
=>
=> a(2)² + b(2) = a+b + a + b + d
=> 4a + 2b = 2a + 2b + d
=> 2a + 2b + d = 4a + 2b
=> d = 2a,.
_________________
∴ Common difference of the AP is 2a,.
_____________________________________________________________
Hope it Helps!!
=> Mark as Brainliest,..
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