sum of first three of an AP is 33 and product of first and third term exceeds
the second term by 2a find AP
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The sum of the first three terms of an A.P. is 33. If the product of the first and the third term exceeds the second term by 29, find the A.P.
Asked by Topperlearning User | 22nd Sep, 2017, 03:16: PM
Expert Answer:
Let the terms in AP be (a - d), a, (a + d).
Sum of the three terms = a - d + a + a + d = 3a
3a = 33
a = 11
Also, from the given information, we have:
(a - d)(a + d) = a + 29
a2 - d2 = 11 + 29 = 40
121 - d2 = 40
d2 = 81
d = 9
Thus, the AP is
2, 11, 20, … or 20, 11, 2, …