Sum of first three term is 33 if product of first and third term exceeds second term by 29 find ap
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Let the first 3 terms of AP: a - d, a, a + d
Given:
(a - d) + a + (a + d) = 3a = 33
a = 11
(a - d)*(a + d) = a + 29
a^2 - d^2 = a + 29
11^2 - d^2 = a + 29
121 - d^2 = 11 + 29
121 - d^2 = 40
d^2 = 121 - 40
d^2 = 81
d = 9
A.P: 11 - 9, 11, 11 + 9 ....
A.P: 2, 11, 18 ...... ——> Answer
Given:
(a - d) + a + (a + d) = 3a = 33
a = 11
(a - d)*(a + d) = a + 29
a^2 - d^2 = a + 29
11^2 - d^2 = a + 29
121 - d^2 = 11 + 29
121 - d^2 = 40
d^2 = 121 - 40
d^2 = 81
d = 9
A.P: 11 - 9, 11, 11 + 9 ....
A.P: 2, 11, 18 ...... ——> Answer
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