Sum of first three terms of a gp is 13 and the sum of next three terms is 351,find gp
Abhishekranjan1:
shshshhshshshshhs
Wt?
i think it last three terms
ya
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sum of 1st 3 terms of gp=13
sum of last 3 terms of gp=351
sn=n/2[2a+(n-1)d]
s3=3/2[2a+(n-1)d]----------(1)
sum of last 3 terms of gp=351
sn=n/2[2a+(n-1)d]
s3=3/2[2a+(n-1)d]----------(1)
sorry by mistake i have posted
It's ok
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