Question

sum of five consecutive odd integers is 275

Answer 1

Each two consecutive odd integers differ each other by 2.

Thus, let the 5 consecutive odd integers be x - 4,  x - 2,  x,  x + 2  and  x + 4.

$(x-4)+(x-2)+x+(x+2)+(x+4)=275 \\ \\ \\ x-4+x-2+x+x+2+x+4=275 \\ \\ \\ 5x=275 \\ \\ \\ x=\displaystyle \frac{275}{5} \\ \\ \\ x=\bold{55} \\ \\ \\ x+2=\bold{57} \\ \\ \\ x+4=\bold{59} \\ \\ \\ x-2=\bold{53} \\ \\ \\ x-4=\bold{51}$

Thus the 5 consecutive odd integers are 51, 53, 55, 57 and 59.

$\LARGE \textbf{51 + 53 + 55 + 57 + 59 = 275}$

Answer 2

Answer:

Step-by-step explanation:

let 3 consecutive be x,x+2,x+4,x+6,x+8

Then

5x+20=275

5x=255

x=51 (1)

x+2=51+2 =53 (2)

x+4=51+4=55 (3)

x+6=51+6=57 (4)

x+8=51+8=59 (5)

(1)(2)(3)(4)(5) are 5 odd consecutive integers