Question

Sum of four consecutive integers are 266. What r the integers?

Answer 1

let 1 integer x
2 integer x+1
3 integer x+2
4 integer x+3

x+x+1+x+2+x+3=266
4x+6=266
4x=260
x=65
1 integer= 65
2integer = 66
3integer= 67
4 integer= 68

Answer 2

let the four consecutive integers be x, x+1, x+2, x+3
Their sum is 266
So, x+x+1+x+2 +x+3=266
or 4x+6=266
or 4x=266-6
or 4x=260
or x=260/4
or x =65

so, 1st integer is 65
2nd integer is 65+1=66
3rd integer is 65+2=67
4th integer is 65+3=68

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