Question

Sum of four consecutive integers is 130 what is the third number in the sequence

Answer 1

Let the first number (the smallest one) be x

We have x+(x+1)+(x+2)+(x+3) = 130

4x + 6 = 130

4x = 124

x = 124/4 = 31

x = 31

x+1= 32

x+2= 33

x+3 = 34

So the third number in the sequence is 33