Sum of four consecutive integers is 130 what is the third number in the sequence
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Let the first number (the smallest one) be x
We have x+(x+1)+(x+2)+(x+3) = 130
4x + 6 = 130
4x = 124
x = 124/4 = 31
x = 31
x+1= 32
x+2= 33
x+3 = 34
So the third number in the sequence is 33
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