sum of four consecutive numbers is 32 and the ratio of their first and last , middle two terms is 7:15 find the numbers
GDhruv:
then, you have to add them together.
You will get 'a' as 8. Then you have to substitute 'a' in the ratio equation
then you will get d
I JUST REALISED THAT THE QUESTION HE POSTED IS WRONG LOL
it should be this:
The sum of four consecutive numbers in an AP is 32 and the ratio of the product of the first and the last term to the product of two middle terms is 7 : 15. Find the numbers.
But whatever question I did that only that your question says but instead of a-3d I took a-2d is it wrong
hahah
that question is correct bro answers are 2 10 and 14
yes
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I gave you hint now solve it further hope helpful
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this is wrong
answer is +/- 2
therefore, the numbers will be 2, 6, 10 and 14
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