Question

sum of four consecutive numbers is 66 . find the numbers

Answer 1

Solution;

Given: sum of 4 consecutive numbers = 66.

To find: the value of 4 numbers

Let the number be,
a, a+1, a+2 and a+3

So,
(a)+(a+1)+(a+2)+(a+3)=66
                                4a+6 =66
                                      4a=66-6
                                      4a=60
                                        a=15
Hence the 4 numbers are:
            a=15,
        a+1=15+1=16,
        a+2=15+2=17,
        a+3=15+3=18,
The 4 numbers are 15,16,17,18.

                   Hope it Helps!!

Answer 2

Answer:

consecutive numbers are 15, 16, 17 and 18.

Step-by-step explanation:

Let the four consecutive numbers be x, x+1, x+2 and x+3

According to the question,

x+x+1+x+2+x+3 = 66

=> 4x + 6 = 66

=> 4x = 66 - 6

=> 4x = 60

=> x = 60/4

=> x= 15

Therefore, consecutive numbers are 15, 16, 17 and 18.

____________________

Verification :

15 + 16 + 17 + 18 = 66

=> 66 = 66

Hence verified!