Question

Sum of four consecutive odd numbers is 40. Find the numbers.​

Answer 1

Answer:

four consecutive odd no are = n , n+2 , n+4 , n+6

n = odd no

n + n+2 +n+4+n+6 = 40

4n + 12 = 40 ..

4n = 40-12 = 28

n = 28/4 = 7 .,..

putting value

.

n = 7

n+2 = 9

n+4 = 11

n+6 = 13 ...

Answer 2

Answer:

7,9,11,13

Step-by-step explanation:

let one of the odd number be 'x'

other two odd numbers= (x+2) , (x+4) ,(x+6)

x + (x+2) + (x+4) ,( x+6)= 40

x+x+2+x+4+x+6=40

4x+12=40

4x=40-12

4x=28

x= 28÷4

x=7

x+2=9

x+4=11

x+6=13