sum of four consecutive term of an ap is 122 the fourth term is 23 less than the sum of the first and third term find d
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Step-by-step explanation:
1st+2nd+3rd+4th=122
a+(a+d)+(a+2d)+(a+3d)=122
4a+6d=122
2a+3d=61 [÷by 2]
4th=(1st+3rd)−23
(a+3d)=(a+a+2d)-21
On simplifying,
a-d=23
a=26
d=3
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