Question

sum of four consecutive term of an ap is 122 the fourth term is 23 less than the sum of the first and third term find d​

Answer 1

Step-by-step explanation:

heres ur answer

pls follow

Answer 2

Answer:

3

Step-by-step explanation:

1st+2nd+3rd+4th=122

a+(a+d)+(a+2d)+(a+3d)=122

4a+6d=122

2a+3d=61 [÷by 2]

4th=(1st+3rd)−23

(a+3d)=(a+a+2d)-21

On simplifying,

a-d=23

a=26

d=3