sum of four consecutive terms which are AP is 32 and the ratio of the product of the first and last to the product of two middle terms is 7:5 find the number
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Step-by-step explanation:
Let the 4 terms be a+3d,a-d,a+d,a+3d
Given a-3d+a-d+a+d+a+3d=32
4a=32
A=8
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