sum of four terms of an arithmetic sequences hundred and first term is 1 what is third term
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Step-by-step explanation:
S4 = 100 , a = 1
S4 = 100
n/2[2×a + (n-1)d] = 100
4/2 [2 × 1 + (4 - 1) d] = 100
2 (2 + 3d) = 100
2+3d = 100/2
2 + 3d = 50
3d = 50 - 2
3d = 48
d = 48/3 = 16
Finding 3rd term
an = a + (n - 1)d
a3 = 1 + (3-1) 16
= 1 + 2×16
= 1 + 32
= 33
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