Question

sum of frist positive intege ( natural number ) sn​

Answer 1

Hello,Buddy!!

Refer The Attachment ⤴️

• Sn = n(n+1)/2

@MrMonarque♡

Hope It Helps You ✌️ [tex][/tex]

Answer 2

QUESTION :- Sum of first 'n' positive integers.

SOLUTION :-

$\sf{S_n = 1 + 2 + 3 + 4 + 5 + 6 + till \: n \: term}$

Here,

a (First Term) = 1

d (Common Difference) = $\sf{a_2 - a_1}$ = 2 - 1 = 1

Using the formula of sum of nth terms,

$\sf{S_n = \frac{n}{2}[2a + (n - 1)d]} \\ \: \: \: \: \: \sf{= \frac{n}{2}[2(1) + (n - 1)(1)]} \\ \: \: \: \: \: \sf{= \frac{n}{2}[2 + n - 1]} \\ \: \: \: \: \: = \sf{ \frac{n}{2}[n + 1]}$

$\therefore \sf \green{S_n} = \red{\frac{n(n + 1)}{2}}$