Math, asked by arghasarkar53, 1 month ago

Sum of indices:simplify:(3a/b to the power -1) +(2b/a to the power-1)​

Answers

Answered by soumitkar5
0

Answer:

2b^2+3a^2 / 6ab

Step-by-step explanation:

(3a/b)^-1 + (2b/a)^-1

= b/3a + a/2b

= 2b*b + 3a* a / 6ab

= 2b^2+3a^2 / 6ab

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