Question

sum of infinite gp is 16 and the sum of the squares of it's term is 768/5 find common ratio nad 4 th term .
​

Answer 1

Answer:

Let first term be a and common ratio be r.

So sum is a/(1−r)=x

For other series sum is a2/(1−r2)=y

So y/x2=(1−r)/(1+r)

So by componendo and dividendo

r=(x2−y)/(x2+y)

Answer 2

Answer

0

crankybirds30

Genius

5K answers

710.5K people helped

Answer:

Let first term be a and common ratio be r.

So sum is a/(1−r)=x

For other series sum is a2/(1−r2)=y

So y/x2=(1−r)/(1+r)

So by componendo and dividendo

r=(x2−y)/(x2+y)