sum of infinite series 1 + 1 by 3 + 1 by 3 square + infinity is
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Step-by-step explanation:
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Step-by-step explanation:
As written (with 3n as the final term), the sum is infinity.
A more typical problem about the sum of a decreasing (converging) geometric series would be this:
1+131+132+133+⋯+13n
The formula for the sum of a converging geometric series is:
Sn=a1(1−rn)1−r, where a1is the first term and r is the common ratio.
Use this formula with a1=1 and r=13 :
Sn=1(1−(13)n)1−13=123=32
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