Question

sum of integer is 69 . one of the integer is - 42 find the other
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Answer 1

$\bf \: \underline{Given} :$ ↴

$\sf \: Sum \: of \: two \: integers \: is \: 69$

$\sf \: One \: of \: the \: integer \: is \: - 42$

$\bf \: \underline{To \: find }:$ ↴

$\sf \: We \: have \: to \: find \: the \: another \: number.$

$\bf \star \: \underline{So, \:Let's \:Start} \:\star$

$\sf Let\: the \:another\: number \:be \:x.$

$\red{\longrightarrow \sf\: -42 \: +\: x\: =\: 69}$

$\longrightarrow\sf\: x \:= \:69\: - (-42)$

$\longrightarrow\sf\: x \:= \:69\: + \:42$

$\longrightarrow\sf\:x \:= \:111$

$\sf \pink{So,\: the\: another \:number \:is\: 111}$

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$\sf Let's \: verify \:our \:answer.$

$\boxed {\green{\sf -42 \: + \: 111 \: = \: 69}}$

$\sf Hence\: the \:answer \:is \: 111$

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$\sf \underline{Rules \: used \: to\: solve\: this \: question} :$

$\boxed{\begin{array} {c|c} \sf{ +,- } & \sf{ - } \\ \dfrac{\qquad\qquad}{} & \dfrac{\qquad}{} \\ \sf{- , +} & \sf{ - } \\ \dfrac{\qquad\qquad}{} & \dfrac{\qquad}{} \\ \sf{+,+} & \sf{ + } \\ \dfrac{\qquad\qquad}{} & \dfrac{\qquad }{} \\ \sf{-,-} & \sf{ + }\end{array}}$

Answer 2

$\bf \: The \: another \: number \: is \: 111.$

$\large \: \bf Explanation :$

$\bf \: Let \: the \: another \: number \: be \: Z.$

$\bf \: -42 \: + \: Z \: = \: 68$

$\bf \: Z \: = \: 69 - (-42)$

$\bf \: Z = \: 69 + 42$

$\bf \: Z \: = \: 111$

$\underline{{ \underline{ \boxed{ \red{\rm \: So, \: the \: another \: number \: is \: 111. }}}}}$