Question

sum of m terms of an ap 4m^2+2a. find 4th term​

Answer 1

Answer:

28

Step-by-step explanation:

Sn=4m^2+2a

first term=T1=4(1)^2+2a=4+2a

sum of 2 terms= S2=4(2)^2+2a=16+2a

2nd term =t1+t2=16+2a

4+2a+t2=16+2a

t2=12

sum of three terms=t2+t2+t3=4(9)+2a=36+2a

4+2a+12+t3=36+2a

t3=20

sum of 4 terms=t1+t2+t3+t4=4(16)+2a=64+2a

t4=64+2a-4-2a-12-20=28

so t4=28

Answer 2

Answer:

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