Sum of m terms = sun of n terms, sum of m+n terms?
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sum of m+n terms =0 is required answer
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The sum of pp terms of an arithmetic series is p2(2a+(p−1)d)p2(2a+(p−1)d) where aa is the first term and dd is the difference between each term.We can express what mm and nn equal to by putting pp equal to nn and mm respectively.Then to get m+nm+n, we simply add the new ways of expressing mm and nn.
Now to get the sum, we take p=m+np=m+n, but that yields an expression that is way too big to handle, and since this is a textbook problem, I am assuming the answer is short and succint.
Also, can you guys actually show me the example of a series where sum of mm terms is nn and vice versa?
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