Question

Sum of money becomes 16 times in 4 years at si . the rate of intetest is

Answer 1

$Let \: the \: sum \: ( Principal ) = P ,$

$Times (T) = 4 \: years ,$

$Amount (A) = 16P,$

$Simple \: Interest (I) = A - P$

$= 16P - P$

$= 15P$

$Let \: Rate \: of \: Interest = R$

$\boxed { \pink {R = \frac{100 \times I }{ P T }}}$

$R = \frac{ 100 \times 15P }{ P \times 4 }$

$\implies R = 25 \times 15$

$\implies R = 375\%$

Therefore.,

$\red{ Rate \: of \: Interest }\green {= 375\%}$

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Answer 2

ANSWER✔

$\large\underline\bold{GIVEN,}$

$\sf\dashrightarrow \:time(t) =4years.$

$\sf\dashrightarrow amount(A)= 16 \times p=16p$

$\sf\therefore\text{ let the Rate be x }$

$\large\underline\bold{TO\:FIND,}$

$\sf\dashrightarrow The\:rate\:of\: interest$

✯.FORMULA IN USE,

$\large{\boxed{\bf{ \star\:\: Rate= \dfrac{100\times I }{ p\times T}\:\: \star}}}$

$\large\underline\bold{SOLUTION,}$

$\sf\therefore\text{ finding the value of simple intrest.}$

WE KNOW

$\large\underline\bold{simple\:interest(I)= A-P}$

$\sf\implies 16p-p$

$\sf\implies 15p$

$\large{\boxed{\bf{ \star\:\: simple\:interest(I)= 15p\: \star}}}$

NOW,

PUTTING THE VALUES IN THE GIVEN FORMULA.WE GET,

$\sf\therefore Rate= \dfrac{100\times I }{ p\times T}$

$\sf\implies x= \dfrac{ 100\times 15p}{p \times 4}$

$\sf\implies x= \dfrac{ \cancel{100} \times 15\: \cancel{p}}{\cancel{p} \times \cancel{4}}$

$\sf\implies x= 25 \times 15$

$\sf\implies x = 375\%$

$\large{\boxed{\bf{ \star\:\: rate(x)= 375\%\:\: \star}}}$

$\large\underline\bold{THE\:RATE\:OF\:INTEREST\:IS\:375\%.}$

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