sum of money double itself in 3 years at compound interest in how many years does it become 16 times itself
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Answer:
Step-by-step explanation:
Let the principal be p and rate percent be r.
ATP,
p(1+r/100)^3=2p
(1+r/100)^3=2
(1+r/100)=2^(1/3)
Let it become 16 times in t years
Now,
p(1+r/100)^t=16p
(1+r/100)^t=16
Substituting value of (1+r/100),
2^(1/3)(t)=2^4
Since bases are equal powers will also be equal
t/3=4
t=12
Thus, the sum becomes 16 times in 12 years.
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