sum of money is distributed among some people. The first one get 1 rs the second one get 1 rs more then first, the 3rd one gets 2 rs more then the second and the 4th one gets 3rs more then the 3rd and so on. The last person gets rs 67. Find the number of persons.
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first gets RE 1
second gets RE 2
third gets RE 2 more than second = RE 4
fourth gets RE3 more than third term = RE 7
so
fifth gets RE 4 more than fourth term= RE 11
as this
twelve gets RE 11 more than eleventh term =. RE 67
therefore 12 no of person. are present
second gets RE 2
third gets RE 2 more than second = RE 4
fourth gets RE3 more than third term = RE 7
so
fifth gets RE 4 more than fourth term= RE 11
as this
twelve gets RE 11 more than eleventh term =. RE 67
therefore 12 no of person. are present
Niroj1:
formula is tn=a+(n-1)*d where difference increases by its previous term so d=2* previous term
nope difference is increasing apparently by calculating with this sum with formula the answer is not the same try it
ok
i need a proper formula for this sum
tn(n-1)+d
tn=t(n-1)*d
sorry tn=tn(n-1)+d
can u solve it please
what is the answer
12
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