Question

sum of money is invested at half yearly compound interest rate 5% If the difference of principals at the end of 6 and 12 months is Rs126. Find (i) the sum of money invested (ii)Amount at end of 1(1/2)years(one whole one by two years)​

Answer 1

Solution:-

(i) The sum of money invested = RS 4032.

(i) The sum of money invested = RS 4032.(ii) The amount at the end of first year = RS 4326.12.

To find:+

(i) The sum of money invested = RS 4032.(ii) The amount at the end of first year = RS 4326.12. To find:

(i) The sum of money invested = RS 4032.(ii) The amount at the end of first year = RS 4326.12. To find:(i) The sum of money invested ?

(i) The sum of money invested = RS 4032.(ii) The amount at the end of first year = RS 4326.12. To find:(i) The sum of money invested ?(ii) The amount at the end of first year ?

(i) The sum of money invested = RS 4032.(ii) The amount at the end of first year = RS 4326.12. To find:(i) The sum of money invested ?(ii) The amount at the end of first year ?

Given data:

(i) The sum of money invested = RS 4032.(ii) The amount at the end of first year = RS 4326.12. To find:(i) The sum of money invested ?(ii) The amount at the end of first year ?Given data:Rate of interest = 5%

(i) The sum of money invested = RS 4032.(ii) The amount at the end of first year = RS 4326.12. To find:(i) The sum of money invested ?(ii) The amount at the end of first year ?Given data:Rate of interest = 5%Difference between the principle at the end of 6 months and 12 months = RS.126

Formula:-

$ci = p(1 + \frac{r}{100} ) {}^{n}$

$x + y + \frac{xy {}^{} }{100}$

Rate of interest = 5%

Rate of interest = 5%Since calculated half-yearly, rate of interest for 6 months = 2.5%

Rate of interest = 5%Since calculated half-yearly, rate of interest for 6 months = 2.5%Difference between the principle at the end of 6 months and 12 months = RS 126

Rate of interest = 5%Since calculated half-yearly, rate of interest for 6 months = 2.5%Difference between the principle at the end of 6 months and 12 months = RS 126Difference between the rate of interest at the end of 6 months and 12 months is calculated as,

$x + y + \frac{xy}{100}$

$x + y + \frac{xy}{100}$

$2.5 + 2.5 + \frac{2.5 \times 2.5}{100}$

$2.5$

$5.625 - 2.5$

$3.125$

3.125

3.125Thus 3.125 = 126

3.125Thus 3.125 = 126Then 100 = ?

3.125Thus 3.125 = 126Then 100 = ? =

$\frac{126 \times 100}{3.125}$

Therefore,

Therefore,(i) The sum of money invested = RS 4032

Therefore,(i) The sum of money invested = RS 4032(ii) The amount at the end of first year,

$ci = 4032(1 + \frac{2.5}{100} ) {}^{2}$

$4032( \frac{102.5}{100} ) {}^{2}$

$4032(1.022) {}^{2}$

$4032 \times 1.050625$

$ci = 4326.12$

4326.12

4326.12

4326.12 To solve more:

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