Math, asked by koduriramarao, 9 months ago

sum of multiples of 5 between 107 and 253 is [in progressions]

Answers

Answered by kmd806112
2

Answer:

5220

Step-by-step explanation:

Let Progression is = 110,115,120,.................250

Then

First term (a) = 110

Common Diffrence (d) = a2 - a1 = 115 -110 = 5

And

Last Term (an) = 250

Let find no. of terms

An = a + (n - 1)d

250 = 110 + (n - 1)5

250 - 110/5 = (n - 1)

140/5 = n - 1

28 + 1 = n

n = 29

Sum of multiples of 5 between 107 and 253 is = n/2(a + an)

= 29/2(110 + 250)

= 29/2(360)

= 29*180

= 5220

The sum of multiples of 5 between 107 and 253 is 5220

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