sum of multiples of 5 between 107 and 253 is [in progressions]
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2
Answer:
5220
Step-by-step explanation:
Let Progression is = 110,115,120,.................250
Then
First term (a) = 110
Common Diffrence (d) = a2 - a1 = 115 -110 = 5
And
Last Term (an) = 250
Let find no. of terms
An = a + (n - 1)d
250 = 110 + (n - 1)5
250 - 110/5 = (n - 1)
140/5 = n - 1
28 + 1 = n
n = 29
Sum of multiples of 5 between 107 and 253 is = n/2(a + an)
= 29/2(110 + 250)
= 29/2(360)
= 29*180
= 5220
The sum of multiples of 5 between 107 and 253 is 5220
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