Question

sum of n 2n 3n terms of an ap are S1 s2 and s3 respectively prove that S3 =3(s2-s3).​

Answer 1

Answer:

Prove that S3=3(S2-S1). The sum of n 2n 3n terms of an AP are S1 S2 S3 respectively. Prove that S3=3(S2-S1).

Step-by-step explanation:

We have to prove that  S3 = 3 ( S2 – S1).

R.H.S = 3 (S2 – S1)

 = S3

 = L.H.S

⇒ S3 = 3 ( S2 – S1).

Answer 2

plz refer to this attachment