Sum of n consecutive numbers is 1000 find product
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Let the ten consecutive numbers be
X, x+1, x+2, x+3, x+4, x+5, x+6, x+7, x+8, x+9.
So,their sum = 1000
Then,
X+x+1+x+2+x+3+x+4+x+5+x+6+x+7+x+8+x+9 = 1000
10x + 45 = 1000
10x = 1000 - 45
10x = 955
X = 955/10
X = 95.5
So, the numbers are = 95.5, 96.5, 97.5, 98.5, 99.5, 100.5, 101.5, 102.5, 103.5, 104.5
Now, you can find their products.
X, x+1, x+2, x+3, x+4, x+5, x+6, x+7, x+8, x+9.
So,their sum = 1000
Then,
X+x+1+x+2+x+3+x+4+x+5+x+6+x+7+x+8+x+9 = 1000
10x + 45 = 1000
10x = 1000 - 45
10x = 955
X = 955/10
X = 95.5
So, the numbers are = 95.5, 96.5, 97.5, 98.5, 99.5, 100.5, 101.5, 102.5, 103.5, 104.5
Now, you can find their products.
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