Question

Sum of n term of the series√3+√12+√27+√48+__is ​

Answer 1

Answer:

n√3

Step-by-step explanation:

By formula,

$t _{n} = a + (n - 1)d$

$a = \sqrt{3} \\ d = \sqrt{12} - \sqrt{3} = 2 \sqrt{3} - \sqrt{3} = \sqrt{3}$

$t _{n} = \sqrt{3} + (n - 1) \sqrt{3} \\ t _{n} = \sqrt{3} (1 + n - 1) \\ t _{n} = n\sqrt{3}$

Hence the nth term is n√3

Answer 2

Answer:

√3,√12,√27

a=√3

d=√12-√3

=2√3-√3

=√3

the next term of the series is √27+√3=3√3+√3=4√3=√48 please mark me as brainliest